Calculate the amount of the substance, which is 222 kg of calcium chloride. How many ions of each type

Calculate the amount of the substance, which is 222 kg of calcium chloride. How many ions of each type will contain this amount? What is the mass fraction of chlorine in salt?

Decision:
M (CaCl₂) = 111 g / mol
n (CaCl₂) = 222/111 = 2 mol
N (Ca) = 2 * 1 = 2
N (Cl) = 2 * 2 = 4
w (CI) = 2 * 35.5 / 111 = 0.64
Answer: 111 g / mol, 2.4



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