Calculate the amount of water in a mass of 36 grams

M (H2O) = Mr (H2O) = Ar (H) * N (H) + Ar (O) * N (O) = 1 * 2 + 16 * 1 = 18 g / mol;
n (H2O) = m (H2O) / M (H2O) = 36/18 = 2 mol.



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