Calculate the angle between straight lines MN and KL if M (2; 0; 1) N (-2; 1; 2) K (0; 3; -2) L (-4; 0; 1).

1) Find the coordinates of the vectors MN and KL. To do this, subtract the coordinates of its beginning from the coordinates of the end of the vector. We have: MN = {-2 – 2; 10; 2 – 1} = {-4; one; 1}, KL = {-4 – 0; 0 – 3; 1 – (-2)} = {-4; -3; 3}.
2) Now we find the scalar product of these vectors and their lengths: | MN | = √ ((- 4) 2 + 12 + 12) = 3√2, | KL | = √ ((- 4) 2 + (-3) 2 + 32) = √ (34), MN * KL = (-4) * (-4) + 1 * (-3) + 1 * 3 = 16.
3) Now you can cosine the angle between the straight lines: cos (φ) = (MN * KL) / (| MN | * | KL |) = 8√ (17) / 51.
ANSWER: 8√ (17) / 51.



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