# Calculate the area and perimeter of a rectangle if its length is 5 1/6 cm and width is 3 1/3

**Calculate the area and perimeter of a rectangle if its length is 5 1/6 cm and width is 3 1/3 cm more than it is long.**

To begin with, let’s remember how the area and perimeter of a rectangle are calculated. The area of a rectangle is equal to the product of length and width:

S = ab.

The perimeter of the rectangle is equal to the sum of the lengths of all its sides, since the opposite sides in the rectangle are pairwise equal, we find its perimeter by the formula:

P = 2 * (a + b).

According to the conditions of the problem, we only know the length of the rectangle and the fact that its width is 3 1/3 more than its length. First, find the width of the rectangle, and then calculate the area and perimeter:

5 1/6 + 3 1/3 = 31/6 + 10/3 = 31/6 + 20/6 = 51/6 = 8 3/6 = 8 1/2 cm.

S = 5 1/6 * 8 1/2 = 31/6 * 17/2 = 527/12 = 43 11/12 cm².

P = 2 * (5 1/6 + 8 1/2) = 2 * (31/6 + 17/2) = 2 * 82/6 = 82/3 = 27 1/3 cm.