Calculate the area and perimeter of a rectangle whose length is 90 dm and the width is 6 times less.

The solution of the problem:
The area of a rectangle is equal to the product of its length and width. The perimeter of a rectangle is the sum of the length and width times two.
1. Let’s calculate what the width of the rectangle is.
90/6 = 15 decimeters.
2. Find out what the area of the rectangle is.
90 * 15 = 1350 square decimeters.
3. Calculate the perimeter of the rectangle.
(90 + 15) * 2 = 210 decimeters.
Answer: The area of the rectangle is one thousand three hundred and fifty square decimeters, the perimeter of the rectangle is two hundred and ten decimeters.