Calculate the area of a rhombus if one of its diagonal is 20 dm and the other is 17 dm.

The diagonals of the rhombus at the intersection point are halved and divide the rhombus into four equal triangles.

Then AO = AC / 2 = 20/2 = 10 dm.

ОВ = ВД / 2 = 17/2 = 8.5 dm.

Determine the area of the triangle AOB.

Saov = AO * ВO / 2 = 10 * 8.5 / 2 = 42.5 dm2.

Then Savsd = 4 * Saov = 4 * 42.5 = 170 dm2.

Answer: The area of the rhombus is 170 dm2.



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