Calculate the area of a trapezoid ABC with bases AB and AC if BC = 13 cm, AD = 27 cm, CD = 10 cm, angle D = 30 degrees

From the top of the C obtuse angle, draw the height CH.

In a right-angled triangle CDH, Sin30 = CH / CD.

СН = СD * Sin30 = 10 * 1/2 = 5 cm.

Let’s calculate the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (13 + 27) * 5/2 = 150/2 = 75 cm2.

Answer: The area of the trapezoid is 75 cm2.



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