Calculate the area of a trapezoid ABCD with bases AD and BC if AD = 24, BC = 15, CD = 10, angle D = 90 degrees.

Since, by condition, the angle ADC = 90, then the lateral side of the CD is also the height of the trapezoid, then the area of the trapezoid will be equal to:

Savsd = (ВС + АD) * СD / 2 = (15 + 24) * 10/2 = 195 cm2.

Answer: The area of the trapezoid is 195 cm2.



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