Calculate the area of a trapezoid ABCD with bases AD and BC if BC is 13 cm and AD = 27 cm
May 2, 2021 | education
| Calculate the area of a trapezoid ABCD with bases AD and BC if BC is 13 cm and AD = 27 cm CD = 10 cm and an angle of 30 degrees.
Let’s build the height of the trapezoid CH.
In a right-angled triangle CDK, the angle CDH = 30, then the leg of the CH lies against it, and therefore is equal to half the length of the hypotenuse CD. CH = CD / 2 = 10/2 = 5 cm.
Determine the area of the trapezium ABCD.
Savsd = (ВС + АD) * СН / 2 = (13 + 27) * 5/2 = 100 cm2.
Answer: The area of the trapezoid is 100 cm2.
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