Calculate the area of an isosceles trapezoid whose height is 5 cm, and the base is 6 cm and 14 cm.

The area of an isosceles trapezoid S is defined as the product of its midline L by the height H.
To calculate the length of the midline, it is necessary to add both bases of the trapezoid A, B and divide by two.
L = (A + B) / 2.
L = (6 + 14) / 2.
L = 10 cm.
Now let’s find the area.
S = L * H.
S = 10 * 5.
S = 50 cm2.
Answer: the area of the trapezoid is 50 cm2.