Calculate the area of the triangle between the coordinate axes and the straight line 4x + 3y-24 = 0.

This triangle is rectangular. It is enough to find out the legs that go along the coordinate axes from the origin. Let x = 0. Then:

3y – 24 = 0
y = 8

Now let us take y = 0. Substitute:

4x = 24
x = 6

We don’t need hypotenuse. We consider one of the legs as the height and calculate:

S = 1/2 * x * y = 1/2 * 6 * 8 = 24 units ²

Answer: 24 units ².