Calculate the average force of soil resistance if a body with a mass of 2 kg, thrown from a height of 250 m vertically

Calculate the average force of soil resistance if a body with a mass of 2 kg, thrown from a height of 250 m vertically downward with an initial speed of 20 m / s, plunged into the ground to a depth of 1.5 m.

Data: m (thrown body weight) = 2 kg; h (starting altitude) = 250 m; V (initial speed) = 20 m / s; hz (depth of immersion of the body in the ground) = 1.5 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To calculate the average resistance of the soil, we will use the equality: ΔE = A; m * V ^ 2/2 + m * g * h = F * hz, whence F = (m * V ^ 2/2 + m * g * h) / hz.

Let’s perform the calculation: F = (2 * 20 ^ 2/2 + 2 * 10 * 250) / 1.5 = 3.6 * 10 ^ 3 N (3.6 kN).

Answer: The average soil resistance is 3.6 kN.