Calculate the chemical amount of acetic acid that can be neutralized with an alkali solution

Calculate the chemical amount of acetic acid that can be neutralized with an alkali solution weighing 40 g with a mass fraction of sodium hydroxide of 25%

Given:
m solution (NaOH) = 40 g
ω (NaOH) = 25%

Find:
n (CH3COOH) -?

1) CH3COOH + NaOH => CH3COONa + H2O;
2) m (NaOH) = ω * m solution / 100% = 25% * 40/100% = 10 g;
3) n (NaOH) = m / M = 10/40 = 0.25 mol;
4) n (CH3COOH) = n (NaOH) = 0.25 mol.

Answer: The amount of CH3COOH substance is 0.25 mol.