Calculate the current strength in the conductor, the resistivity of which is 0.017 Ohm * mm² / m

| September 15, 2021 | education

Calculate the current strength in the conductor, the resistivity of which is 0.017 Ohm * mm² / m, the length is 200 m and the cross-section is 0.6 mm², with a voltage of 68V on it.

ρ = 0.017 Ohm * mm² / m.

L = 200 m.

S = 0.6 mm².

U = 68 V.

I -?

The strength of the current in the conductor I is directly proportional to the voltage at its ends U and inversely proportional to the resistance of the conductor R: I = U / R – Ohm’s law for a section of the circuit.

Since the conductor is homogeneous and has a cylindrical shape, its resistance R is expressed by the formula: R = ρ * L / S, where L is the length of the conductor, S is the cross-sectional area, ρ is the resistivity of the substance from which the conductor is made.

I = U * S / ρ * L.

I = 68 V * 0.6 mm² / 0.017 Ohm * mm² / m * 200 m = 12 A.

Answer: in the conductor, the current strength reaches the value I = 12 A.



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