Calculate the efficiency of the lever if it is used to lift a weight of 200 kg to a height of 5 cm by applying

| August 12, 2021 | education

Calculate the efficiency of the lever if it is used to lift a weight of 200 kg to a height of 5 cm by applying a force of 500 N to the other shoulder. The point of application of the force dropped by 40 cm

When lifting the load, useful work was performed against the force of gravity F1, which is equal to:
F1 = mg = 200 kg * 10 m / s ^ 2 = 2000 N (g is the acceleration of gravity).

The value of the useful work Ap when moving the load to the height h1:

Ap = F1h1 = 2000 N * 0.05 m = 100 J.

Work A2 performed by force F2 = 500 N while moving the point of application by the value h2 = 0.4 m:

A2 = F2h2 = 500 N * 0.4 m = 200 J.

The efficiency of the lever η is equal to the ratio of the useful work to the total work performed:

η = (Ap / Ao) * 100% = (100 J / 200 J) * 100% = 50%.

Answer: 50%.



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