Calculate the efficiency of the lever with which a 150 kilogram weight is evenly lifted to a height of 6

Calculate the efficiency of the lever with which a 150 kilogram weight is evenly lifted to a height of 6 centimeters. while the other lever to which a force of 450 N was applied dropped by 25 centimeters.

1) Let the lever have done useful work A floor = m * g * h, where m = 150 kg; g = 0.98 m / s ^ 2; h = 6 cm = 0.06 m. All parameters are converted to the SI system.

Then A floor = 150 kg * 9.8 m / s ^ 2 * 0.06 m = 88.2 N * m = 88.2 J.

2) The expended work of the lever Az = F * H, where F = 450 N; H = 25 cm = 0.25 m.

Then A z = 450 N * 0.25 m = 112.5 N * m = 112.5 J.

3) Efficiency = A floor / A z * 100% = (88.2 J / 112.5 J) * 100% = 78.4%.

Answer: efficiency = 78.4%.