Calculate the efficiency of the lever with which a weight of 245 kg was evenly lifted to a height of 6 m

| May 26, 2021 | education

Calculate the efficiency of the lever with which a weight of 245 kg was evenly lifted to a height of 6 m, while a force of 500 N was applied to the long arm of the lever, and the point of application of this force dropped by 0.3 m.

As you know, the efficiency of the lever n is equal to the ratio of the work done Ac to the expended work Az: n = Ac / Az.

The work done Ac = P1 * h1, where P1 = 245 kg * 9.8 m ^ 2 / c ^ 2 – the weight lifted to a height of h1 = 6 m.

The expended work Az = P2 * h2, where P2 = 500 N is the applied force, h2 = 0.3 m. Let’s make all the calculations and determine the efficiency n:

n = Ac / Az * 100% = 245 kg * 9.8 m ^ 2 / s ^ 2 * 6 m / 500N * 0.3 m * 100% = 96.04 * 100%. That is, the efficiency turned out to be very large, most likely there is an error in the task, namely, h1 = 6cm, not 6m. Then the efficiency is n = 96%.



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