Calculate the H2 needed to reduce 140 g of copper oxide.
| May 30, 2021 | education
Reduction of copper oxide with hydrogen to free copper.
CuO + H2 = Cu + H2O.
The number of mol of oxide is.
n (CuO) = m / Mr = 140 g / 79.5 g / mol = 1.76 mol.
The number of mol of hydrogen and oxide will be equal based on the reaction equation.
n (CuO) = n (H2) = 1.76 mol.
The volume of hydrogen reacted.
V (H2) = n • Vm = 1.76 mol • 22.4 mol / L = 39.45 L.
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