Calculate the inductance of the solenoid if the current in it changes by 50A per second. In this case, an EMF

Calculate the inductance of the solenoid if the current in it changes by 50A per second. In this case, an EMF of self-induction of 0.08V appears at the ends of the solenoid winding

These tasks: ΔI (change in the current in the winding of the solenoid taken) = 6 A; Δt (duration of current change) = 1 s; ε (EMF, which appeared at the ends of the solenoid winding) = 0.08 V.

We express the inductance of the solenoid taken from the calculation formula for the EMF: ε = | L * ΔI / Δt |, therefore, L = ε * Δt / ΔI.

Calculation: L = 0.08 * 1/50 = 0.0016 H = 1.6 * 10-3 H = 1.6 mH.

Answer: The taken solenoid solenoid has an inductance of 1.6 mH.