Calculate the length of the base side of a regular triangular pyramid with volume 2 and height 2√3.

We apply the formula for the volume of the pyramid and express the area of the base through it.

Vpyr = Sosn * SO / 3.

Sbas = 3 * Vpyr / SO = 3 * 2 * / 2 * √3 = 3 / √3 = √3 cm2.

The ABC triangle is equilateral, then all its angles are equal to 600.

Then the area of the triangle ABC will be equal to:

Saavs = AB * BC * Sin60 / 2 = BC2 * √3 / 4.

BC2 = 4 * Savs / √3 = 4 * √3 / √3 = 4.

BC = AB = AC = 4 cm.

Answer: The length of the side of the base is 2 cm.