Calculate the m of hexane that can be obtained by reacting 9.42 g of chloropropane with 3.22 g of sodium.

To solve the problem, write down the equation:
2С3Н7Cl + 2Na = C6H14 + 2NaCl – Wurtz reaction, hexane obtained;
M (C3H7Cl) = 78.5 g / mol;
M (Na) = 22.9 g / mol;
M (C6H14) = 86 g / mol.
We find the amount of mol of sodium propane chloride, if the mass is known:
Y (C3H7Cl) – m / M = 9.42 / 78.5 = 0.12 mol (lack of substance);
Y (Na) = m / M = 3.22 / 22.9 = 0.14 mol.
We make calculations according to the equation, according to the substance in short supply. We make the proportion:
0.12 mol (C3H7Cl) – X mol (C6H14);
2 mol -1 mol hence, X mol (C6H14) = 0.12 * 1/2 = 0.06 mol.
Let’s calculate the mass of hexane by the formula:
m (C6H14) = Y * M = 0.06 * 86 = 5.16 g.
Answer: the mass of hexane is 5.16 g.



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