Calculate the mass: a) 0.3 mol H2O B) 0.5 mol KCL C) 4 mol CuO D) 0.2 mol Fe2O3

a) 0.3 mol H2 O
m = n * M
m = 0.3 * 18 = 5.4 g
B) 0.5 mol KCL
m = n * M
m = 0.5 * 74.5 = 37.25 g
C) 4 mol CuO
m = n * M
m = 4 * 80 = 320 g
D) 0.2 mol Fe2O3
m = n * M
m = 0.2 * 160 = 32 g



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