Calculate the mass and amount of hydrochloric acid that can react with 56 g of ferric hydroxide three

Calculate the mass and amount of hydrochloric acid that can react with 56 g of ferric hydroxide three, if this produces ferric chloride three.

Given:
m (Fe (OH) 3) = 56 g

To find:
m (HCl) -?
n (HCl) -?

1) 3HCl + Fe (OH) 3 => FeCl3 + 3H2O;
2) n (Fe (OH) 3) = m / M = 56/107 = 0.5 mol;
3) n (HCl) = n (Fe (OH) 3) * 3 = 0.5 * 3 = 1.5 mol;
4) m (HCl) = n * M = 1.5 * 36.5 = 55 g.

Answer: The mass of HCl is 55 g; the amount of substance is 1.5 mol.