Calculate the mass and amount of oxygen reacted with copper if 4 g of copper (II) oxide is formed.
| November 22, 2020 | education
1) Let’s compose the reaction equation: 2Cu + O2 ==> 2CuO
2) Determine the amount of copper oxide: n (CuO) = m (Cuo) / M (CuO) = 4g / 80g / mol = 0.05 mol, The reaction equation follows: n (O2): n (CuO) = 1: 2 = 0.025 mol
3) Find the mass of oxygen: m (O2) = n (O2) * M (O2) = 0.025 mol * 32g / mol = 0.8 g
Answer: m (O2) = 0.8g
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