Calculate the mass and amount of phosphorus substance required for the reaction with 56 liters of oxygen.

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In this case, 2 molecules of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in 56 liters of oxygen.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N O2 = 56 / 22.4 = 2.5 mol;

With this amount of oxygen, 2.5 / 5 x 4 = 2 mol of phosphorus will react.

Let’s calculate its weight.

To do this, we multiply the amount of the substance by its molar weight.

M P = 31 grams / mol;

m P = 31 x 2 = 62 grams;