Calculate the mass and amount of sulfur that has reacted with iron, if you get 44 g of iron (II) sulfide

Given:

m (FeS) = 44 g

To find:

m (S) -?

n (S) -?

Solution:

1) S + Fe => FeS;

2) n (FeS) = m / M = 44/88 = 0.5 mol;

3) n (S) = n (FeS) = 0.5 mol;

4) m (S) = n * M = 0.5 * 32 = 16 g.

Answer: The amount of substance S is 0.5 mol; weight – 16 g.



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