Calculate the mass and amount of the salt substance obtained by reacting 200 g of a 24.5%

Calculate the mass and amount of the salt substance obtained by reacting 200 g of a 24.5% sulfuric acid solution with an excess of copper oxide.

Given:

m (solution) = 200 g,

w = 24.5%,

m (substances) -?

n-?

Decision:

Let’s find the mass of sulfuric acid by the formula:

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (200 g × 24.5%): 100% = 49 g.

Let’s find the amount of sulfuric acid substance.

n = m: M.

M (H2SO4) = 2 + 32 + 64 = 98 g / mol.

n = 49 g: 98 g / mol = 0.5 mol.

Let’s compose the equation for the reaction between sulfuric acid and copper oxide:

H2SO4 + CuO → CuSO4 + H2O

1 mol of sulfuric acid accounts for 1 mol of copper sulfate CuSO4.

The substances are in quantitative ratios of 1: 1. The amount of acid substance and the amount of CuSO4 substance are the same.

n (CuSO4) = 0.5 mol.

Find the mass of CuSO4 by the formula: m = n × M,

M (CuSO4) = 64 + 32 + (16 × 4) = 160 g / mol.

m = 160 g / mol × 0.5 mol = 80 g.

Answer: m = 80 g; n (CuSO4) = 0.5 mol.