Calculate the mass and amount of the salt substance obtained by the interaction of sulfuric acid weighing 58.8 g

Calculate the mass and amount of the salt substance obtained by the interaction of sulfuric acid weighing 58.8 g with an excess of copper hydroxide (2). Chemical reaction equation: Cu (OH) 2 + H2SO4 = CuSO4 + 2H2O.

Given:
m (H2SO4) = 58.8 g

To find:
m (salt) -?
n (salt) -?

1) H2SO4 + Cu (OH) 2 => CuSO4 + 2H2O;
2) n (H2SO4) = m / M = 58.8 / 98 = 0.6 mol;
3) n (CuSO4) = n (H2SO4) = 0.6 mol;
4) m (CuSO4) = n * M = 0.6 * 160 = 96 g.

Answer: The mass of CuSO4 is 96 g; the amount of substance is 0.6 mol.