Calculate the mass and amount of the substance copper (II) hydroxide, which was formed

Calculate the mass and amount of the substance copper (II) hydroxide, which was formed by the interaction of substance X with a mass of 35 g with copper silicate.

substance x – NaOH
Given:
m (NaOH) = 35 g
To find:
m (Cu (OH) 2)
n (Cu (OH) 2
Decision:
CuSiO3 + NaOH = Cu (OH) 2 ↓ + Na2SiO3
n (NaOH) = m: M = 35 g: 40 g / mol = 0.875 mol
n (NaOH): n (Cu (OH) 2) = 2: 1
n (Cu (OH) 2) = 0.875 mol: 2 = 0.438 mol
m (Cu (OH) 2) = n * M = 0.438 mol * 98 g / mol = 42.92 g
Answer: m (Cu (OH) 2) = 42.92 g; n (Cu (OH) 2) = 0.438 mol