Calculate the mass and amount of the substance (mol) of barium oxide formed

Calculate the mass and amount of the substance (mol) of barium oxide formed during the decomposition of 80 g of barium carbonate containing 3% impurities

The decomposition reaction of barium carbonate when heated is described by the following chemical equation:

BaCO3 = BaO + CO2 ↑;

Let’s calculate the chemical amount of barium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M BaCO3 = 137 + 12 + 16 x 3 = 197 grams / mol;

N BaCO3 = 80 x 0.97 / 197 = 0.3939 mol;

The same molar amount of barium oxide could theoretically be synthesized.

Let’s find its weight.

M BaO = 137 + 16 = 153 grams / mol;

m BaO = 0.3939 x 153 = 60.2667 grams;