Calculate the mass and amount of the substance of the resulting salt, if 0.2 mol

Calculate the mass and amount of the substance of the resulting salt, if 0.2 mol of magnesium and 0.2 mol of formic acid are taken for the reaction.

Given:
n (HCOOH) = 0.2 mol
n (Mg) = 0.2 mol

To find:
n (salt) -?

Decision:
1) Write the equation of a chemical reaction:
Mg + 2HCOOH => (HCOO) 2Mg + H2 ↑;
2) Compare the amount of HCOOH and Mg:
The amount of HCOOH is in short supply, therefore, calculations will be carried out for it;
3) Find the amount of substance (HCOO) 2Mg (taking into account the coefficients in the reaction equation):
n ((HCOO) 2Mg) = n (HCOOH) / 2 = 0.2 / 2 = 0.1 mol.

Answer: The amount of salt substance (HCOO) 2Mg (magnesium formate) is 0.1 mol.



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