Calculate the mass and amount of water substance, which is formed according to the reaction

Calculate the mass and amount of water substance, which is formed according to the reaction equation: Fe2O3 + H2 – Fe + H2O, if 16 grams of iron oxide enters into the reaction (3)

Let’s write the reaction equation:

Fe2O3 + 3H2 = 2Fe + 3H2O

M (Fe2O3) = 2 * 56 + 3 * 16 = 160 g / mol (found from the periodic table);
n (Fe2O3) = m / M = 16/160 = 0.1 mol (n is the number of moles of phosphoric acid);
from n (Fe2O3) = 1 mol it turns out n (H2O) = 3 mol (according to the equation, the coefficients in front of the formulas), then from n (Fe2O3) = 0.1 mol we get n (H2O) = 3 * 0.1 / 1 = 0.3 mol;
m (H2O) = n (H2O) * M (H2O) = 0.3 * 18 = 5.4 g;
M (H2O) = 2 * 1 + 1 * 16 = 18 g / mol. (Found from the periodic table)

Answer: n (H2O) = 0.3 mol; m (H2O) = 5.4 g.