Calculate the mass and amount of water substance, which is formed according to the reaction equation: Fe2O3 + H2 – Fe + H2O, if 16 grams of iron oxide enters into the reaction (3)
Let’s write the reaction equation:
Fe2O3 + 3H2 = 2Fe + 3H2O
M (Fe2O3) = 2 * 56 + 3 * 16 = 160 g / mol (found from the periodic table);
n (Fe2O3) = m / M = 16/160 = 0.1 mol (n is the number of moles of phosphoric acid);
from n (Fe2O3) = 1 mol it turns out n (H2O) = 3 mol (according to the equation, the coefficients in front of the formulas), then from n (Fe2O3) = 0.1 mol we get n (H2O) = 3 * 0.1 / 1 = 0.3 mol;
m (H2O) = n (H2O) * M (H2O) = 0.3 * 18 = 5.4 g;
M (H2O) = 2 * 1 + 1 * 16 = 18 g / mol. (Found from the periodic table)
Answer: n (H2O) = 0.3 mol; m (H2O) = 5.4 g.
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