Calculate the mass and volume of carbon dioxide released by the action of a solution containing 126 kg

| July 2, 2021 | education

Calculate the mass and volume of carbon dioxide released by the action of a solution containing 126 kg of nitric acid on the excess of calcium carbonate, if the carbon dioxide yield is 80% of the theoretically possible.

m is the mass of the substance
v – amount of substance
Mr – molecular weight
V is the volume of the substance
22.4 l / mol – molar volume of gases

To find the amount of substance, we use the formula v = m / Mr,
Mr (HNO3) = 63 g / mol,
v (HNO3) = 126000/63 = 2000 mol.
In the condition of the problem, it is indicated that calcium carbonate is in excess, which means that we continue the further calculation for nitric acid.
The ratios before nitric acid and carbon dioxide show that the substances are in a 2: 1 ratio.
v (CO2 theory) = 2000/2 = 1000 mol.
According to the condition of the problem, the yield of carbon dioxide is 80% of the theoretically possible, therefore,
v (CO2 practical) = 1000 * 0.8 = 800 mol.
Mr (CO2) = 44 g / mol
m (CO2) = 800 * 44 = 35200 g = 35.2 kg
V (CO2) = 800 * 22.4 = 17920 l



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