Calculate the mass and volume of carbon monoxide 4 obtained by reacting 100 g

Calculate the mass and volume of carbon monoxide 4 obtained by reacting 100 g of limestone containing 20 percent impurities with hydrochloric acid.

Decision:

Let’s compose the equation for the reaction of interaction of limestone with hydrochloric acid:
CaCO3 + 2HCl = CaCl2 + H2O + CO2;

Let’s find a mass of pure limestone:
100 * 0.8 = 80 grams;

Let’s find the molecular weight of limestone:
40 + 12 + 16 * 3 = 100 g / mol;

Let’s find the amount of substance in limestone:
80/100 = 0.8 mol;

Carbon dioxide is preceded by the same coefficient as before limestone. This means that the amount of substance in carbon dioxide is 0.8 mol. Let’s find the mass of carbon dioxide:
0.8 * (12 + 16 * 2) = 0.8 * 44 = 35.2 grams;

Let’s find the volume of carbon dioxide:
0.8 * 22.4 = 17.92 liters.

Answer: the mass of carbon dioxide is 35.2 grams, its volume is 17.92 liters.