Calculate the mass and volume of H2O2 required to obtain 36 g of water.
| December 6, 2020 | education
2H2O2 = 2H2O + O2
n = m / M (Mr) M = Mr Mr (H2O) = 18g / mol M = 18g / mol)
n (H2O) = 36/18 = 2 (mol)
n (H2O) / n * H2O2) = 2/2 according to the reaction condition, next, n (H2O2) = 2 mol
m = n * m (Mr) M = Mr Mr (H2O2) = 2 + 32 = 34 M = 36g / mol
m (H2O) = 2 * 36 = 72 (g)
V = n * Vm V (H2O2) = 2 * 22.4 = 44.8 (l)
Answer: 72g, 44.8L
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