# Calculate the mass and volume of hydrogen that is formed by the interaction of aluminum and chloride acid weighing 73 g.

Metallic aluminum interacts with hydrochloric acid. This forms an aluminum chloride salt and releases elemental hydrogen. The interaction is described by the following chemical equation.
Al + 3HCl = AlCl3 + 3/2 H2;
Let’s determine the chemical amount of hydrochloric acid. To do this, we divide its weight by the molar weight of the acid.
M HCl = 1 + 35.5 = 36.5 grams / mol;
N HCl = 73 / 36.5 = 2 mol;
The chemical amount of released hydrogen will be 2 times less: 2/2 = 1 mol
Let’s find its volume.
For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).
V H2 = 1 x 22.4 = 22.4 liters;
The weight of hydrogen will be:
M H2 = 2 grams / mol;
m H2 = 2 x 1 = 2 grams;

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