Calculate the mass and volume of oxygen required to react with 48 grams of sulfur.

Given:

m (S) = 48 g

To find:

m (O2) -?

V (O2) -?

Decision:

S + O2 = SO2, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of sulfur contained in 48 grams of the substance:

n (S) = m: M = 48 g: 32 g / mol = 1.5 mol;

2) We compose a logical expression:

if 1 mole of S requires 1 mole of O2,

then 1.5 mol S will require x mol O2,

then x = 1.5 mol.

3) Find the mass of oxygen required for the reaction to proceed:

m (O2) = n * M = 1.5 mol * 32 g / mol = 48 g;

4) Find the volume of oxygen:

V (O2) = n * Vm = 1.5 mol * 22.4 l / mol = 33.6 l.

Answer: m (O2) = 48 g; V (O2) = 33.6 liters.