Calculate the mass and volume of the formed gas if 15 grams of ammonia has entered into a reaction with oxygen.

Given:
m (NH3) = 15 g
To find:
V (N2)
m (N2)
Decision:
4NH3 + 3O2 = 2N2 + 6H2O
n (NH3) = m / M = 15 g / 17 g / mol = 1 mol
n (NH3): n (N2) = 4: 3
n (N2) = 1 * 3/4 = 0.75 mol
V (N2) = n * Vm = 0.75 mol * 22.4 l / mol = 16.8 l
m (N2) = n * M = 0.75 mol * 28 g / mol = 21 g
Answer: V (N2) = 16.8 l; m (N2) = 21 g



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