Calculate the mass and volume of the reaction product formed during the combustion of 103 g of sulfur in oxygen.

univerkov | November 22, 2020 | education

Let’s write the reaction equation
S + O2 = SO2
Find n sulfur
n = m / M
n (S) = 103g / 32g / mol = 3.2 mol
n (S) = n (SO2) = 3.2 mol
Then the mass of SO2 = n * M = 3.2 mol * 64 g / mol = 204.8 g
V = n * Vm = 3.2 mol * 22.4 l / mol = 71.68 l

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