Calculate the mass fraction in% of the yield from the theoretically possible, if it is known

Calculate the mass fraction in% of the yield from the theoretically possible, if it is known that 11.2 liters of acithelene were obtained 10 g of benzene.

Given:
V (C2H2) = 11.2 L
m pract. (C6H6) = 10g

Find:
η (C6H6) -?

1) 3C2H2 => C6H6;
2) n (C2H2) = V / Vm = 11.2 / 22.4 = 0.5 mol;
3) n theory. (C6H6) = n (C2H2) / 3 = 0.5 / 3 = 0.17 mol;
4) m theor. (C6H6) = n theory. * M = 0.17 * 78 = 13.26 g;
5) η (C6H6) = m practical. * 100% / m theory. = 10 * 100% / 13.26 = 75.4%.

Answer: The yield of C6H6 is 75.4%.