Calculate the mass fraction of a pure substance in a 300 g sample of limestone if the impurity in it is 10 g.
| January 29, 2021 | education
1. Determine the mass of calcium carbonate in limestone:
m (CaCO3) = m (limestone) – m (impurities) = 300 – 10 = 290 g;
2.Calculate the mass fraction of pure substance in a limestone sample:
w (CaCO3) = m (CaCO3): m (limestone) = 290: 300 = 0.9667 or 96.67%.
Answer: 96.67%.
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