Calculate the mass fraction of a pure substance in a 300 g sample of limestone if the impurity in it is 10 g.

1. Determine the mass of calcium carbonate in limestone:

m (CaCO3) = m (limestone) – m (impurities) = 300 – 10 = 290 g;

2.Calculate the mass fraction of pure substance in a limestone sample:

w (CaCO3) = m (CaCO3): m (limestone) = 290: 300 = 0.9667 or 96.67%.

Answer: 96.67%.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.