Calculate the mass fraction of ferrous sulfate in the solution if 3 liters of water and 180 grams

| August 17, 2021 | education

Calculate the mass fraction of ferrous sulfate in the solution if 3 liters of water and 180 grams of salt were taken to prepare it.

1. Let’s calculate the chemical amount of ferrous sulfate (2):

n (FeSO4) = m (FeSO4): M (FeSO4);

M (FeSO4) = 56 + 32 + 4 * 16 = 152 g / mol;

n (FeSO4) = 180: 152 = 1.1842 mol;

2. find the amount and mass of water in the crystalline hydrate FeSO4 * 7H2O:

n (H2O) = n (FeSO4) * 7 = 1.1842 * 7 = 8.2894 mol;

mcr (H2O) = n (H2O) * M (H2O) = 8.2894 * 18 = 149.2 g;

3.Calculate the mass of ferrous sulfate:

m (FeSO4 * 7H2O) = m (FeSO4) + mcr (H2O) = 180 + 149.2 = 329.2 g;

4.determine the mass of the solution:

m (solution) = ρ (water) * V (water) + m (FeSO4) = 1 * 3000 + 180 = 3180 g;

5.Calculate the mass fraction of vitriol:

w (FeSO4 * 7H2O) = m (FeSO4 * 7H2O): m (solution) = 329.2: 3180 = 0.1035 or 10.35%.

Answer: 10.35%.



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