Calculate the mass fraction of hydrogen chloride that will be released when 5.6 g of aluminum reacts with HCL.

In the condition there is an error: as a result of the reaction, not hydrogen chloride is released, but hydrogen.

Given:
m (Al) = 5.6 g

To find:
V (H2) -?

Decision:
1) Write the reaction equation:
2Al + 6HCl => 2AlCl3 + 3H2 ↑;

2) Find the amount of substance Al:
n (Al) = m (Al) / Mr (Al) = 5.6 / 27 = 0.21 mol;

3) Find the amount of substance H2O (taking into account the reaction equation):
n (Al) = n (Al) * 3/2 = 0.21 * 3/2 = 0.32 mol;

4) Find the volume of released H2:
V (H2) = n (H2) * Vm = 0.32 * 22.4 = 7.2 liters.

Answer: The volume of released H2 is 7.2 liters.