Calculate the mass fraction of impurities in natural limestone if it is known that the decomposition of 120 kg

Calculate the mass fraction of impurities in natural limestone if it is known that the decomposition of 120 kg of this sample produces 48 kg of quicklime.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of the calcium oxide substance.

M CaO = 40 + 16 = 56 grams / mol;

N CaO = 48,000/56 = 857.14 mol;

Let’s calculate the weight of the same amount of lime.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

m CaCO3 = 857.14 x 100 = 85 714 grams;

Let’s calculate the mass fraction of impurities.

K impurities = 1 – m lime / m sample = 1 – 85,714 / 120,000 = 0.286 = 28.6%;