Calculate the mass fraction of oxygen in the NO22 compound, how much oxygen is consumed during

Calculate the mass fraction of oxygen in the NO22 compound, how much oxygen is consumed during the oxidation of copper, if copper oxide weighing 1.6 g is formed

1) The mass fraction of oxygen in NO2 nitrogen dioxide is (16 * 2) / (14 + 16 * 2) = 69.6%.
2) The reaction of oxidation of copper to copper (II) oxide: 2Cu + O2 = 2CuO.
The amount of the formed copper oxide is equal to:
1.6 g: 80 g / mol = 0.02 mol, and oxygen, as can be seen from the reaction, is consumed 2 times less. those. 1/2 * 0.02 = 0.01 mol.