Calculate the mass fraction of sulfur in sulfuric and sulfurous acids. Compare the sulfur content of acids.

univerkov | April 24, 2021 | education

Const: M (S) – molar mass of sulfur (M (S) = 32.076 g / mol); M (H2SO4) is the molar mass of sulfuric acid (M (H2SO4) = 98.078 g / mol); M (H2SO3) is the molar mass of sulfurous acid (M (H2SO4) = 82.07 g / mol).

1) Sulfuric acid: ω (S) 1 = MS / MH2SO4 * 100% = 32.076 / 98.078 * 100% ≈ 32.7%.

2) Sulfurous acid: ω (S) 2 = MS / MH2SO3 * 100% = 32.076 / 82.07 * 100% ≈ 39.1%.

3) Comparison of sulfur content: ω (S) 1 (32.7%) <ω (S) 2 (39.1%).

Answer: ω (S) 1 = 32.7%, ω (S) 2 = 39.1%, the mass fraction of sulfur in sulfurous acid is greater.

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