Calculate the mass fraction of sulfuric acid in the solution formed by mixing 950 g of water and 50 ml of 48% H2SO4 solution.
Calculate the mass of the initial sulfuric acid solution: m = p × V
m1 (pa-pa) (H2SO4) = 1.38 × 50 = 69 gr.
Let’s calculate the acid content in the initial mixture: m (in-va) = w × m (pa-pa)
m (in-va) (H2SO4) = 69 × 0.48 = 33.12 gr.
Calculate the mass of the resulting mixture: m (mixture) = m (in-va) (H2SO4) + m (H2O)
m (mixture) = 33.12 + 950 = 983.12 gr.
Let’s calculate the acid content in the resulting mixture: w2 = m (in-va) (H2SO4) / m (mixture)
w2 = 33.12 / 983.12 × 100% = 3.37%
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