Calculate the mass fractions of Mn, C, O, in the MnCo3 molecule

Find the molar mass MnCO3
M (MnCO3) = 48 + 12 + 55 = 115 g / mol
M (Mn) = 55
W (Mn) = 55: 115 × 100 = 47.8%
M (C) = 12
W (C) = 12: 115 × 100 = 10.4%
M (O) = 48
W (O) = 48: 115 × 100 = 41.7%



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