Calculate the mass fractions of oxygen in substances NO2 PbO2 SO2

univerkov | June 15, 2021 | education

The molar mass (M) of nitrogen is 14 (g \ mol), M (O) 16 (g \ mol), therefore M (NO2) is 14 + 16 * 2 = 46 (g \ mol).
Mass fraction of oxygen: 100% * (16 * 2 (g \ mol) / 46 (g \ mol)) = 69.6%
M (Pb) = 207 (g / mol), M (PbO2) = 207 + 16 * 2 = 239 (g / mol)
Mass fraction of oxygen: 100% * (16 * 2 (g \ mol) / 239 (g \ mol)) = 13.4%
M (S) = 32 (g \ mol), M (SO2) = 32 + 16 * 2 = 64 (g \ mol)
Mass fraction of oxygen: 100% * (16 * 2 (g \ mol) / 64 (g \ mol)) = 50%

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