Calculate the mass of 12.04 per 10 ^ 23 iron oxide molecules.
September 2, 2021 | education
| In this case, according to Avogadro’s law, 1 mol of iron oxide contains 6.02 x 10 ^ 23 (degrees) Then, according to the condition of the problem, we get 12.04 x 10 ^ 23: 6.02 X 10 ^ 23 = 2 (mol)
And this will be in the scales. But first, let’s calculate the molecular weight of iron oxide. m (Fe2O3) = 56 x 2 + 16 x 3 = 160 (g / mol)
Well, 2 moles of this substance will be equal.
160 (g / mol) x 2 mol = 320 (grams)
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